By Honey Brown
Sarah y Heath. Se han encontrado durante l. a. noche. Una riada y una tormenta les han dejado aislados e incomunicados en los angeles montaña. Él está herido; es amable, encantador, muy atractivo. Desde el primer momento, Sarah desconfía. ¿Le ha dado su verdadero nombre? ¿Qué hacía en l. a. montaña sin equipo ni provisiones? ¿Por qué no le cube dónde dejó el coche? ¿Y por qué no parece interesado en que vengan a rescatarles? Están obligados a convivir, en una intimidad forzosa, en el refugio. Pero entonces desaparece el rifle de Sarah, y luego los angeles batería de su móvil. No hay escapatoria. Si quiere salir viva tendrá que seguir el juego al que l. a. empuja este extraño. Un hombre del que sospecha. Y que l. a. atrae.
Una historia intensa, turbadora, íntima, amenazadora, sensual y desasosegante. Un mystery psicológico adictivo y distinto.
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Extra info for A solas con un extrano
15 According to Eq. 42) we may write 15 To achieve this not all Carnot engines operate in the same direction. 4 Entropy 23 qi,0 = T0 qi . , n) in one complete turn around of the system is n n q0 = qi,0 = T0 i=1 i=1 qi . Ti As before, when we compared the thermal efficiency of the Carnot engine to the X-machine (on p. e. n 0= n E= qi,0 − i=1 qi −wtotal . i=1 =q0 =0 Because wtotal ≤ 0 if Kelvin’s postulate is correct, we must have q0 ≤ 0 and consequently n qi ≤ 0. Ti i=1 Taking the limit n → ∞ and qi → dq we have dq ≤ 0.
However, we need z before we can compute concrete numbers. We may look up z in a table. In Ref. 007 JK −1 g−1 at T = 300 K and P = 105 Pa. For an ideal gas C P = C V + n R (cf. p. 9 Thus, according to Eq. 82) the temperature reaches absolute zero at around 3 · 104 m. Before we compare this to the experimental data we want a corresponding pressure profile P(h), which is readily obtained by inserting Eq. 82) into Eq. 80). We find d ln P = −z If z Ho dh . 84) where P0 is the pressure at h = 0. 84) is called barometric formula.
29) Comparison of Eqs. 29) immediately yields Eq. 27), which in combination with the ideal gas law yields Eq. 24). 1 Whether or not our assumption of point particles already implies ideality is a matter of definition of the inter particle interactions. 34 2 Thermodynamic Functions Finally we take another look at the entropy. 30) cf. 51). Using Eq. e. d E = (3/2)n RdT , and once again Eq. 7) we find d S = n R d ln T 3/2 − d ln V . 31) Integration yields the generalization of Eq. 20) T To S(T, V ) − S(To , Vo ) = n R ln 3/2 V .
A solas con un extrano by Honey Brown